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5 August, 00:00

The balanced equation for the reaction of nitrogen gas and fluorine gas is

N2 (g) + 3 F2 (g) → 2 NF3 (g)

What is the limiting reactant if 25 N2 molecules are allowed to react with 75 F2 molecules?

a. N2

b. F2

c. NF3

d. There is no limiting reactant: the reactants are present in stoichiometrically equivalent amounts

e. More information is needed to solve this problem

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Answers (1)
  1. 5 August, 00:19
    0
    We don't have a limiting reactant.

    The reactants are present in stoichiometrically equivalent amounts.

    Option D is correct

    Explanation:

    Step 1: Data given

    Molecules N2 = 25 molecules

    Molecules F2 = 75 molecules

    Number of Avogadro = 6.02 * 10^23 / moles

    Step 2: Calculate moles N2

    Moles N2 = molecules N2 / number of Avogadro

    Moles N2 = 25 / 6.02 * 10^23

    Moles N2 = 4.15 * 10^-23 moles

    Step 3: Calculate moles F2

    Moles F2 = 75 molecules / 6.02 * 10^23

    Moles F2 = 1.25 * 10^-22 moles

    Step 4: Calculate limiting reactant

    For 1 mol N2 we need 3 moles F2 to produce 2 moles NF3

    For 4.15 * 10^-23 moles N2 we need 1.25 * 10^-22 moles F2

    OR

    For 25 molecules N2 we need 75 molecules F2

    Both reactants will completely react.

    This means we don't have a limiting reactant.

    The reactants are present in stoichiometrically equivalent amounts.

    Option D is correct
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