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Mollie Frye
Chemistry
18 April, 22:50
What is the [OH-] in a solution of ph 3.00?
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Rylie Suarez
18 April, 23:06
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PH = 3, pOH = 14-3 = 11
[OH-] = 10^ (-pOH) = 10^ (-11) = 1E-11 or 1*10^-11
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