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George Miller
Chemistry
11 May, 17:36
How many molecules are there in 79g of Fe2O3?
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Alivia Trevino
11 May, 17:55
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There are approximately 160 grams in 1 mol of fe203 molecules therefore there would be 79/160 = 0.49375 mols of fe203 molecules in 79 grams therefore 5 atoms in total for each molecule of fe203 therefore 79/160 * 5 = 79/32=2.46875 mols in atoms
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