Ask Question
2 December, 16:36

A student wishes to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl.

What volume of the

12.0 M HCl should he/she start with?

+5
Answers (1)
  1. 2 December, 17:01
    0
    4.74 mL

    Explanation:

    M1V1 = M2V2

    12.0M*V1 = 0.875M*65.0 mL

    V1 = 0.875M*65.0 mL/12.0M = 4.74 mL
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A student wishes to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl. What volume of the 12.0 M HCl should he/she start with? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers