How many moles of gas occupy 98 L at a pressure of 2.8 atmosphere and a temperature of 292 K

Let's assume that the gas has ideal gas behavior.

Then we can use ideal gas equation,

PV = nRT

Where,

P = Pressure of the gas (Pa)

V = volume of the gas (m³)

n = number of moles (mol)

R = Universal gas constant (8.314 J mol ⁻¹ K⁻¹)

T = temperature in Kelvin (K)

The given data for the gas is,

P = 2.8 atm = 283710 Pa

V = 98 L = 98 x 10 ⁻³ m³

T = 292 K

R = 8.314 J mol ⁻¹ K⁻¹

n = ?

By applying the formula,

283710 Pa x 98 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 292 K

n = 11.45 mol

Hence, moles of gas is 11.45 mol.