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24 March, 08:50

How many milliliters of a 4.0-molar solution

of HCl are needed to completely neutralize

60 milliliters of a 3.2-molar solution of NaOH?

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Answers (1)
  1. 24 March, 09:01
    0
    HCl + NaOH → NaCl + H2O

    No. of moles of NaOH = MV/1000

    = 3.2X60/1000

    = 0.192 mol

    **M is your concentration of solution, V is the volume of solution either in cm³ or mL cuz they are equal**

    1 mol of NaOH reacted with 1 mol of HCl. No. of moles of HCl needed to react with 0.192mol of NaOH

    = 0.192x1/1

    = 0.192mol

    Volume of HCl = no. of moles x 1000 / M

    = 0.192 x 1000 / 4.0

    = 48mL
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