A solution is prepared by mixing 2.88 mol of acetone with 1.45 mol of cyclohexane at 30°C. 2nd attempt Calculate the χacetone and χcyclohexane in the vapor above the solution. P°acetone = 229.5 torr and P°cyclohexane = 97.6 torr.

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Casey

Chemistry

23 January, 08:53

A solution is prepared by mixing 2.88 mol of acetone with 1.45 mol of cyclohexane at 30°C. 2nd attempt Calculate the χacetone and χcyclohexane in the vapor above the solution. P°acetone = 229.5 torr and P°cyclohexane = 97.6 torr.

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Holden Clayton · Answer 1

First c alculate the mole fraction of each substance:

acetone: 2,88 mol : (2,88 mol + 1,45 mol) = 0,665.

cyclohexane: 1,45 : (2,88 mol + 1,45 mol) = 0,335.

Raoult's Law:

P (total) = P (acetone) · χ (acetone) + P (cyclohexane) · χ (cyclohexane).

P (total) = 229,5 torr · 0,665 + 97,6 torr · 0,335.

P (total) = 185,3 torr.

χ for acetone: 229,5 torr · 0,665 : 185,3 torr = 0,823.

χ for cyclohexane: 97,6 torr · 0,335 : 185,3 torr = 0,177.