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19 May, 12:13

If 25.0 moles of gasohol (C2H60) burns this way, how many moles of oxygen are

needed?

C2H60 + 3 O2 - -> 2 CO2 + 3 H20

a) 75.0 moles

b) 37.5 moles

c) 16.7 moles

d) 8.3 moles

+3
Answers (1)
  1. 19 May, 12:34
    0
    a. 75 mol O2

    Explanation:

    1 mol C2H6O - > 3 mol O2

    25 mol C2H6O - > x

    x = (25 mol C2H6O * 3 mol O2) / 1 mol C2H6O

    x = 75 mol O2
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