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Simone Estrada
Chemistry
15 December, 18:20
How many atoms of iodine are in 12.75g of CaI2
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Marcelo Booth
15 December, 18:46
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0.5 * 10²³ atoms of iodine
Explanation:
Given dа ta:
Mass of calcium iodide = 12.75 g
Number of atoms of iodine = ?
Solution:
First of all we will calculate the number of moles of calcium iodide.
Number of moles = mass / molar mass
Number of moles = 12.75 g / 293.9 g/mol
Number of moles = 0.04 mol
In one mole of calcium iodide there are two moles of iodine.
Thus in 0.04 moles:
0.04 mol * 2 = 0.08 moles of iodine
Now we will use the Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms, ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 * 10²³ is called Avogadro number.
1 mole = 6.022 * 10²³ atoms
0.08 moles of iodine * 6.022 * 10²³ atoms / 1 mol
0.5 * 10²³ atoms of iodine.
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