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9 January, 13:04

A calorimeter contains 100 g of water at 39.8 ºC. A 8.23 g object at 50 ºC is placed inside the calorimeter. When equilibrium has been reached, the new temperature of the water and metal object is 40 ºC. What type of metal is the object made from?

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  1. 9 January, 13:21
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    When equilibrium has been reached so, according to this formula we can get the specific heat of the unknown metal and from it, we can define the metal as each metal has its specific heat:

    Mw*Cw*ΔTw = Mm*Cm*ΔTm

    when

    Mw → mass of water

    Cw → specific heat of water

    ΔTw → difference in temperature for water

    Mm→ mass of metal

    Cw→ specific heat of the metal

    ΔTm → difference in temperature for metal

    by substitution:

    100g * 4.18 * (40-39.8) = 8.23 g * Cm * (50-40)

    ∴ Cm = 83.6 / 82.3 = 1.02 J/g.°C

    when the Cm of the Magnesium ∴ the unknown metal is Mg
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