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9 October, 01:39

What is the pH of a 0.028M solution (pH=-log (M))

A) 3.56

B) 2.88

C) 1.55

D) 1

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Answers (2)
  1. 9 October, 02:02
    0
    ph = -log (28 x 10^-2)

    = - (log 28 + log10^-2) ie using indices

    = - (1.44 + (-2))

    = - (-0.56)

    = 0.56

    =approximately (1) ans
  2. 9 October, 02:09
    0
    C

    Explanation:

    -log (0.028) = 1.55
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