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17 June, 06:30

If you start with 36.0mL of C4H10 gas at STP, how many grams are of CO2 can you produce if you have excess oxygen gas?

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  1. 17 June, 06:42
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    Mass of CO₂ = 0.352 g

    Explanation:

    Given dа ta:

    Volume of C₄H₁₀ = 36.0 mL (36/1000 = 0.036 L)

    Temperature = 273 K

    Pressure = 1 atm

    Mass of carbon dioxide produced = ?

    Solution:

    Chemical equation:

    2C₄H₁₀ + 13O₂ → 10H₂O + 8CO₂

    Number of moles of C₄H₁₀:

    PV = nRT

    n = PV/RT

    n = 1 atm * 0.036 L / 0.0821 atm. L / mol. K * 273 k

    n = 0.036 atm. L / 22.4 atm. L / mol

    n = 0.002 mol

    C₄H₁₀ : CO₂

    2 : 8

    0.002 : 8/2*0.002 = 0.008 mol

    Mass of CO₂:

    Mass = number of moles * molar mass

    Mass = 0.008 mol * 44 g/mol

    Mass = 0.352 g
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