During Trial 2, what allowed you to determine that aluminum was the limiting reactant? Check all that
apply.
All of the copper dissolved.
All of the aluminum dissolved.
The solution turned clear.
The number of grams of copper (II) chloride used in the reaction was greater than the number of
grams of aluminum.
The molar ratio of copper (II) chloride to aluminum was greater than 3:2, the equation's molar ratio.
Answers (1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “During Trial 2, what allowed you to determine that aluminum was the limiting reactant? Check all that apply. All of the copper dissolved. ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers
You Might be Interested in
When iron rusts it no longer conducts electricity this is because
Answers (1)
Changes in the forms of energy are called energy creations energy conversions energy chemicals energy conjunctions
Answers (1)
Find the mass, in grams, of 5.00*10^23 molecules of F2
Answers (1)
What's needed to build a neutron atom
Answers (1)
A substance with a definite shape and volume is what phase of matter?
Answers (2)
New Questions in Chemistry
Ocean constitutes most of ___ of water a) Evaporation b) Precipitation c) Condensation d) Transpiration e) Sublimation Don't choose a random letter.
Answers (2)
In the reaction, Zn + HCl-> ZnCl2 + H2, 25 grams Zn are reacted with 17.5 grams HCl. How many grams of H2 will be produced? A. 0.382 g of H2 B. 0.479 g of H2 C. 0.7865 g of H2 D. 0.484 g of H2
Answers (1)
Is nail varnish soluble?
Answers (2)
What is the periodic trend for atomic size from top and bottom in a group? From left to right in a period?
Answers (2)
Which planets' orbits is the belt located between the main asteroid belt?
Answers (1)