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26 December, 10:26

Calculate the heat released when 25.0 grams of water freezes at 0 degree Celsius.

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  1. 26 December, 10:50
    0
    = 8350 joules

    Solution and explanation:

    The heat of fusion refers to the quantity of heat released when a given amount of water freezes. For example, 1 g of water releases 334 J when it freezes at 0°C.

    Therefore; For 25.0 g of water.

    Heat released = Mass of water * heat of fusion

    = 25 g * 334 J/g

    = 8350 Joules

    Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.
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