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10 November, 20:21

How many grams of nh3 can be produced from 3.99 mol of n2 and excess h2?

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  1. 10 November, 20:37
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    Standard equation: N2 (g) + 3H2 (g) = = >2NH3 (g), so through stoichiometry, (3.99 mol N2) (2 mol NH3/1 mol N2) (17.031g of NH3/1 mol NH3), yielding 135.90738g of NH3
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