A 10 L container holds 4 moles of gat at a pressure of 305 kPa. What is the temperature in Kelvins?

91.768 K

Explanation:

To solve these problems, we can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant (R = 0.082 L. atm/mol. K),

T is the temperature of the gas in K.

The temperature of the gas = PV/nR.

P = 305.0 kPa/101.325 = 3.01 atm, V = 10.0 L, R = 0.082 L. atm/mol. K, n = mass/molar mass = 4.0 mol.

∴ T = PV/nR = (3.01 atm) (10.0 L) / (4.0 mol) (0.082 L. atm/mol. K) = 91.768 K.