The density of liquid mercury is 13.69 g/cm^3. How many atoms of mercury are in a 15.0 cm^3 sample? Use "E" for "x10" and use sig figs.

The formula is m = D x V

D = 13.69 g/cm^3.

V = 15.0 cm^3

the mass of the liquid mercury is m = 13.69 g/cm^3 x 15.0 cm^3 = 195g

the molar mass of Hg is 200,

1 mole of Hg = 200g Hg, so #mole of Hg = 195 / 200 = 0.97 mol

but we know that

1 mole = 6.022 E23 atoms

0.97 mole=?

6.022 E23 atoms x 0.97 / 1 mole = 5.84 E23 atoms