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16 August, 10:54

when 824 J of heat is added to 9 grams of oil at 30°c, the temperature increases to 87°C. what is the specific heat of the oil

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  1. 16 August, 11:06
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    c = 1.61 j/g.°C

    Explanation:

    Given dа ta:

    Mass of oil = 9 g

    Heat added = 824 j

    Initial temperature = 30°C

    Final temperature = 87°C

    Specific heat of oil = ?

    Solution:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = Final temperature - final temperature

    ΔT = 87°C - 30°C

    ΔT = 57 °C

    Q = m. c. ΔT

    824 j = 9 g * c * 57 °C

    824 j = 513 g. °C * c

    c = 1.61 j/g.°C
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