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25 December, 03:01

Molarity, abbreviated M, is defined as the concentration of a solution expressed as moles of solute per liter of

solution. How many milliliters of 4.00 M H2SO4 are required to react with 1.60 g of Cuo according to CuO (s) + H2SO4 (aq) - ->CuSO4 (aq) + H2O (l)

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  1. 25 December, 03:20
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    5 mL H₂SO₄

    Explanation:

    The equation for the reaction is;

    CuO (s) + H₂SO₄ (aq) → CuSO₄ (aq) + H₂O (l)

    We are given;

    Molarity of H₂SO₄ = 4.00 M

    Mass of CuO = 1.6 g

    We are required to calculate the volume of H₂SO₄

    First; we need to determine the number of moles of CuO

    Moles = Mass : Molar mass

    Molar mass of CuO = 79.545 g/mol

    Mass of Cu = 1.6 g

    Moles of CuO = 1.6 g : 79.545 g/mol

    = 0.020 moles

    Second; we determine the number of moles of H₂SO₄ that reacted with CuO.

    From the equation 1 mole of CuO reacts with 1 mole of H₂SO₄

    Therefore;

    0.020 moles of CuO will react with 0.020 moles H₂SO4

    Third; we calculate the volume of H₂SO₄

    Molarity is given by dividing the number of moles by volume.

    Thus;

    Volume = Moles : Molarity

    In this case;

    Volume = 0.020 moles : 4.00 M

    = 0.005 L

    But; 1 L = 1000 mL

    Therefore; Volume = 5 mL

    Hence the volume of H₂SO₄ required to react with CuO is 5 mL
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