A mineral contains only a metal, M, and sulfur. If analysis indicates that a 44.9 g sample of the mineral contains 2.1 g of M, what mass of M (g) is contained in 329 g of the mineral?

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Chemistry

29 October, 16:16

A mineral contains only a metal, M, and sulfur. If analysis indicates that a 44.9 g sample of the mineral contains 2.1 g of M, what mass of M (g) is contained in 329 g of the mineral?

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Answers (2)

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Terrance Mcconnell · Answer 1

In a 329 grams mineral, we have 15.4 grams of metal M

Explanation:

Step 1: Data given

Mass of the sample = 44.9 grams

The mineral contains: 2.1 grams of M

Step 2: Calculate mass % of M

mass % of M = (mass M / total mass sample) * 100 %

mass % of M = (2.1 grams / 44.9 grams) * 100 %

mass % of M = 4.677 %

Step 3: Calculate the mass of M in a 329 grams

Mass % = (4.677 grams / 100 %) * 329 grams

Mass % = 0.04677 * 329 grams

Mass % = 15.4 grams

In a 329 grams mineral, we have 15.4 grams of metal M

Hahn · Answer 2

15.38 g is the mass for M in the 329 g of sample

Explanation:

Mineral's formula: MS

Our sample weighs 44.9 g

Mass of M: 2.1 g

Our new sample weighs 329 g

We may solve this by a rule of three:

44.9 g of sample contain 2.1 g of M

329 g of sample will contain (329. 2.1) / 44.9 = 15.38 g