Determine the ammonia concentration of an aqueous solution that has a ph of 11.00. the equation for the dissociation of nh3 (kb = 1.8 * 10-5) is determine the ammonia concentration of an aqueous solution that has a ph of 11.00. the equation for the dissociation of nh3 (kb = 1.8 * 10-5) is 1.8 * 10-2 m

Question

Marley Payne

Chemistry

12 August, 08:57

Determine the ammonia concentration of an aqueous solution that has a ph of 11.00. the equation for the dissociation of nh3 (kb = 1.8 * 10-5) is determine the ammonia concentration of an aqueous solution that has a ph of 11.00. the equation for the dissociation of nh3 (kb = 1.8 * 10-5) is 1.8 * 10-2 m

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Neil · Answer 1

When the dissociation equation of NH3 is:

NH3 (aq) + H2O ↔ NH4 (aq) + OH - (aq)

when Kb = (1.8 x 10^-5)

and when PH+POH = 14

∴ POH = 14 - 11 = 3

when POH = - ㏒[OH]

∴[OH] = 0.001

when [OH] = [NH4+] = 0.001

when Kb = [NH4+][OH-]/[NH4OH]

by substitution:

1.8 x 10^-5 = (0.001) ^2 / [ NH4OH]

∴[NH4OH] = 0.06 M