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6 April, 06:08

A student made two solutions - solution A and solution B. Solution A contained 5 g of copper sulfate in 50 cm3 of water. Solution B contains 10 g of copper sulfate in 100 cm3 of water. The student added solution B to solution A. The student concluded that the new solution is more concentrated because it has more copper sulfate dissolved in it Is the student correct? Explain your answer

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  1. 6 April, 06:36
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    No. The student is wrong.

    Explanation:

    Concentration of solution = mole/volume

    mole of 5 g of copper = 5/63.546 = 0.0787 mole

    Concentration of A = 0.0787/0.05 = 1.57 M

    mole of 10 g of copper = 10/63.546 = 0.1574 mole

    Concentration of B = 0.1574/0.1 = 1.57 M

    The two solution are added together:

    Total concentration = total number of mole/total volume

    = 0.0787 + 0.1574/0.05 + 0.1

    = 0.2361/0.15

    = 1.57 M

    Hence, the new solution has the same concentration with solution A and solution B.

    The student's conclusion was wrong.
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