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28 December, 14:52

You wish to calculate the mass of hydrogen gas that can be prepared from 4.93 g of srh2 and 4.14 g of h2o.

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  1. 28 December, 14:55
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    The maximum amount of hydrogen gas that can be prepared is if all the hydrogen from both compounds is released.

    The hydrogen in 4.94 g of SrH2 is calculated from the mass ratios between Sr and H

    1) H2 in SrH2

    Sr atomic mass = 87.62 g/mol

    H2 molar mass = 2.02 g/mol

    Mass of 1 mol of SrH2 = 87.62 g / mol + 2.02 g/mol = 89.64 g/mol

    Ratio of H2 to SrH2 = 2.02 g H2 / 89.64 g SrH2

    Proportion: 2.02 g H2 / 89.64 gSrH2 = x / 4.93 g SrH2

    => x = 4.93 g SrH2 * 2.02 g H2 / 89.64 g SrH2 = 0.111 g H2

    2) H2 in H2O

    2.02 g H2 / 18.02 g H2O * 4.14 g H2O = 0.464 g H2

    3) Total mass of hydrogen = 0.111 g + 0.464 g = 0.575 g

    Answer: 0.575 g
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