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7 August, 10:38

At this temperature, 0.400 mol of h2 and 0.400 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is present at equilibrium?

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  1. 7 August, 11:05
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    Kc = [HI]² / {[H2] [I2]}

    53.3 = (2x) ² / { (0.400M - x) (0.400M - x) }

    sqrt (53.3) = 2x / (0.400M - x)

    2.92 - 7.30x = 2x

    x = 0.314M

    [HI] = 2x = 0.628M
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