2Al + 3H2SO4 - > Al2 (SO4) 3 + 3H2How many grams of aluminum sulfate would be formed if 250g H2SO4 completely reacted with aluminum?

290.82g

Explanation:

The equation for the reaction is given below:

2Al + 3H2SO4 - > Al2 (SO4) 3 + 3H2 now, let us obtain the masses of H2SO4 and Al2 (SO4) 3 from the balanced equation. This is illustrated below:

Molar Mass of H2SO4 = (2x1) + 32 + (16x4) = 2 + 32 + 64 = 98g/mol

Mass of H2SO4 from the balanced equation = 3 x 98 = 294g

Molar Mass of Al2 (SO4) 3 = (2x27) + 3[32 + (16x4) ]

= 54 + 3[32 + 64]

= 54 + 3[96] = 54 + 288 = 342g

Now, we can obtain the mass of aluminium sulphate formed by doing the following:

From the equation above:

294g of H2SO4 produced 342g of Al2 (SO4) 3.

Therefore, 250g of H2SO4 will produce = (250 x 342) / 294 = 290.82g of Al (SO4) 3

Therefore, 290.82g of aluminium sulphate (Al (SO4) 3) is formed.