How much caco3 is produced if 47.5 moles nh3 are produced?

Question

Eden Key

Chemistry

9 October, 08:12

How much caco3 is produced if 47.5 moles nh3 are produced?

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Answers (1)

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Jamir Lynch · Answer 1

Answer is: 2380 grams of CaCO₃ is produced.

Chemical reaction: Ca (CN) ₂ + 3H₂O → CaCO₃ + 2NH₃.

n (NH₃) = 47,5 mol.

From chemical reaction: n (CaCO₃) : n (NH₃) = 1 : 2.

n (CaCO₃) = 47,5 mol : 2.

n (CaCO₃) = 23,75 mol.

m (CaCO₃) = n (CaCO₃) · M (CaCO₃).

m (CaCO₃) = 23,75 mol · 100,09 g/mol.

m (CaCO₃) = 2380 g.