How many grams of nitric acid will react completely with a block of iron metal that is 4.5 cm by 3.0 cm by 3.5 cm, if the density of iron is 7.87 g/mL? Show all steps of your calculation as well as the final answer. Fe + HNO3 → Fe (NO3) 3 + H2

Question

Saul Massey

Chemistry

9 February, 16:45

How many grams of nitric acid will react completely with a block of iron metal that is 4.5 cm by 3.0 cm by 3.5 cm, if the density of iron is 7.87 g/mL? Show all steps of your calculation as well as the final answer. Fe + HNO3 → Fe (NO3) 3 + H2

+3

Answers (1)

Know the Answer?

Shawn Chang · Answer 1

Balance the equation first:

2 Fe+6 HNO3→2 Fe (NO3) 3+3H2

Then calculate mass of Iron:

4.5*3.0*3.5 cm3 (1 mL1 cm3) (7.87 g Fe1 ml) = 371.86 g Fe

Now use Stoichiometry:

371.86 g Fe * (1 mol Fe55.85 g Fe) * (6 mol HNO32 mol Fe) = 19.97 mol HNO3

Convert moles of nitric acid to grams

19.97 mol HNO3 * (63.01 g HNO31 mol HNO3) = 1258.3 g HNO3