A swimmer swims faster and increases from 80.1 m/s to 80.3 m/s during the last 20 seconds. What is his acceleration?

Question

Maryjane White

Chemistry

25 October, 13:26

A swimmer swims faster and increases from 80.1 m/s to 80.3 m/s during the last 20 seconds. What is his acceleration?

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Daisy Barnett · Answer 1

Answer: (BTW this is a Physics question) 0.01 m/s^2.

Explanation: The formula for acceleration is Δ velocity / Δ time or change in velocity/change in time. We can see find the change in velocity by subtracting v0 (initial velocity) from v (current velocity). v - v0 = 80.3 m/s - 80.1 m/s = 0.2 m/s. The change in time is already given, 20 seconds, so all you have to do is divide 0.2 m/s by 20 seconds to get 0.01 m/s^2.