How much heat was absorbed or lost by the surroundings? use 4.184 j/goc for the specific heat of the solution. put your answer in units of kj and make sure the sign is correct?

Question

Kathy Jacobs

Chemistry

4 January, 11:07

How much heat was absorbed or lost by the surroundings? use 4.184 j/goc for the specific heat of the solution. put your answer in units of kj and make sure the sign is correct?

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Answers (1)

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Eliza Lam · Answer 1

To solve the amount heat that was added or lost in the surrounding, use the formula:

q = m cp dt

where q is the heat

m is the mass of the substance

cp is the specific heat of the subtance

dt is the change in temperature (t2 - t1)

just substitute the given value