Ask Question
13 May, 19:06

An aqueous solution of sodium

hydroxide containing 2g in 200cm^3 of

solution has a concentration of (NaOH =

40). answer in mol/dm^3

+3
Answers (2)
  1. 13 May, 19:12
    0
    2.5*10^-7mol/dm^3

    Explanation:

    Firstly convert the cm^3 to dm^3

    200*1000=200000dm^3

    Calculate the g/dm^3

    2/200000=0.00001g/dm^3

    To calculate mol/dm^3

    Mol/dm^3=mass given/molar mass

    =0.00001/40

    =2.5*10^-7mol/dm^3
  2. 13 May, 19:18
    0
    0.25mol/dm^3

    Explanation:

    Let us calculate the number of mole in 2g of NaOH. This is illustrated below:

    Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

    Mass of NaOH given = 2g

    Number of mole = Mass / Molar Mass

    Number of mole of NaOH = 2/40 = 0.05mole

    Volume = 200cm^3

    1000cm^3 = 1dm^3

    200cm^3 = 200/1000 = 0.2dm^3

    Molarity = mole/Volume

    Molarity = 0.05/0.2

    Molarity = 0.25mol/dm^3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An aqueous solution of sodium hydroxide containing 2g in 200cm^3 of solution has a concentration of (NaOH = 40). answer in mol/dm^3 ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers