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29 May, 03:56

What is a change in heat energy when 40 g of water at 25°C is raise to 60°C

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  1. 29 May, 04:19
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    0.588J

    Explanation:

    m=40g to Kg divide by 1000

    40/1000=0.004kg, c=4.2, change in temperature = 60-25=35

    Q=mxcx change in theta

    Q=0.004x4.2x35

    Q=0.588J
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