What is the volume occupied by a mixture of 0.522 mol of n2 and 0.522 mol of o2 gases at 0.56 atm and 42.7°c?

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Daffy

Chemistry

18 July, 10:21

What is the volume occupied by a mixture of 0.522 mol of n2 and 0.522 mol of o2 gases at 0.56 atm and 42.7°c?

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Cameron Robinson · Answer 1

Assuming ideal gas behavior, we can add the moles of two different substances when they have the same pressure, temperature and volume conditions. Using the ideal gas equation:

PV = nRT

V = nRT/P

V = (0.522+0.522 mol) (0.0821 L-atm/mol-K) (42.7+273 K) / (0.56 atm)

V = 48.32 L