Calculate the molarity of glucose in a solution that which contains 35 g of glucose in 0.16 kg of phenol

Question

Marely Evans

Chemistry

2 January, 12:20

Calculate the molarity of glucose in a solution that which contains 35 g of glucose in 0.16 kg of phenol

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Silky · Answer 1

C (Molarity) = n of solute/V of solution (mol/L)

glucose (C6H12O6) = 180g/mol

glucose 35g = 35g / (180g/mol) = 0.1944mol

We need density of solution here, and I assume it as density of phenol, 1.07g/mL. (I don't know why the question doesn't contain it)

phenol 0.16kg = 0.16kg / (1.07kg/L) = 0.1495L

0.1944mol/0.1495L = 1.300M (mol/L)