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17 January, 18:23

Suppose you have a spherical balloon filled with air at room temperature and 1.0 atm pressure; its radius is 17 cm. You take the balloon in an airplane, where the pressure is 0.87 atm. If the temperature is unchanged, what's the balloon's new radius?,

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  1. 17 January, 18:49
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    Answer: 17.8 cm

    Explanation:

    1) Since temperature is constant, you use Boyle's law:

    PV = constant = > P₁V₁ = P₂V₂

    => V₁/V₂ = P₂/P₁

    2) Since the ballon is spherical:

    V = (4/3) π (r) ³

    Therefore, V₁/V₂ = (r₁) ³ / (r₂) ³

    3) Replacing in the equation V₁/V₂ = P₂/P₁:

    (r₁) ³ / (r₂) ³ = P₂/P₁

    And you can solve for r₂: (r₂) ³ = (P₁/P₂) x (r₁) ³

    (r₂) ³ = (1.0 atm / 0.87 atm) x (17 cm) ³ = 5,647.13 cm³

    r₂ = 17.8 cm
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