A gas occupies 11.2L at 0.860kPa. What is the pressure if the volume

becomes 15.0L

A) 0.64L

B) 1.2kPa

C) 0.64kPa

D) 1.2L

Question

Rudy Bryan

Chemistry

7 April, 23:41

A gas occupies 11.2L at 0.860kPa. What is the pressure if the volume

becomes 15.0L

A) 0.64L

B) 1.2kPa

C) 0.64kPa

D) 1.2L

+5

Answers (2)

Know the Answer?

Genesis Mercado · Answer 1

Answer: Option C) 0.64kPa

Explanation:

Given that,

Original volume V1 = 11.2 L

original pressure P1 = 0.860kPa

New volume V2 = 15.0 L

New pressure P2 = ?

Since pressure and volume are involved while temperature is constant, apply Boyle's law

P1V1 = P2V2

0.860 kPa x 11.2 L = P2 x 15.0L

9.632 kPaL = P2 x 15.0L

P2 = 9.632 kPaL / 15.0L

P2 = 0.64 kPa

Thus, the pressure of the gas is 0.64kPa

Roland White · Answer 2

The correct answer is C) 0.64kPa

A gas occupies 11.2L at 0.860kPa. What is the pressure if the volumebecomes 15.0LA) 0.64LB) 1.2kPaC) 0.64kPaD) 1.2L

A gas occupies 11.2L at 0.860kPa. What is the pressure if the volume

becomes 15.0L

A) 0.64L

B) 1.2kPa

C) 0.64kPa

D) 1.2L