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29 December, 14:58

What is the total mass of a mixture of 3.50x10^22 formula units na2so4, 0.500 mol h2o, and 7.23 g agcl?

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  1. 29 December, 15:00
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    Answer is: mass of the mixture is 24,47 g.

    1) N (Na₂SO₄) = 3,5·10²².

    n (Na₂SO₄) = 3,5·10²² : 6·10²³ 1/mol.

    n (Na₂SO₄) = 0,058 mol.

    m (Na₂SO₄) = 0,058 mol · 142 g/mol.

    m (Na₂SO₄) = 8,24 g.

    2) n (H₂O) = 0,500 mol.

    m (H₂O) = 0,5 mol · 18 g/mol.

    m (H₂O) = 9 g.

    3) m (total) = 8,24 g + 9 g + 7,23 g.

    m (total) = 24,47 g.

    n - amount of substance.
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