A chemist adds 0.50L of a 0.485 M copper (II) sulfate CuSO4 solution to a reaction flask. Calculate the millimoles of copper (II) sulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Question

Manuel Koch

Chemistry

22 October, 05:55

A chemist adds 0.50L of a 0.485 M copper (II) sulfate CuSO4 solution to a reaction flask. Calculate the millimoles of copper (II) sulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

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Answers (1)

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Maren Krause · Answer 1

It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.

Number of millimoles = Molarity * Volume

As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.

Therefore, putting the given values into the above formula as follows.

Number of millimoles = Molarity * Volume

= 0.485 M * 500 mL

= 242.5

Thus, we can conclude that 242.5 millimoles of copper (II) sulfate has been added by the chemist to the flask.