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16 January, 11:16

Express each aqueous concentration in the unit indicated.

a). 25 mg of trichloroethylene in 9.5 L of water, as ppb of trichloroethylene

b). 38 g Cl2 in 1.00x 104 L of water, as ppm Cl2

c). 2.4 ppm F -, as molarity of fluoride ion, in [mol F - / L]

d). 45 ppm NO3 -, as molarity of nitrate ion in [mol NO3 - / L]

e). Why do some scientists prefer to express concentrations of water contaminants in the units ppm and ppb rather than molarity?

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  1. 16 January, 11:22
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    a. ppb of trichloroethylene = 3 * 10⁶ ppb

    b. ppm of Cl₂ = 3.8 ppm

    c. Molarity = 0.0002 mol / L

    d. Molarity = 0.0007 mol / L

    e. For trace amount of concentrations

    Explanation:

    a. Given data

    mass of trichloroethylene = 25 mg

    Volume of water = 9.5 L

    ppb of trichloroethylene = ?

    Solution

    As we know that

    1 L = 1000 milliliters

    9.5 L = 9.5 * 1000

    9.5 L = 9500 millileters (ml)

    we consider 25 mg = 25 millileters

    ppb = (mass of solute / mass of solvent) * 1000,000,000 (1 billion)

    ppb of trichloroethylene = (25 : 9500) * 1000,000,000

    ppb of trichloroethylene = 0.003 * 1000,000,000

    ppb of trichloroethylene = 3 * 10⁶ ppb

    B. Given data

    Mass of Cl₂ = 38 g

    volume of water = 1.00 * 10⁴ L (10000 L)

    ppm of Cl₂ = ?

    Solution

    Volume of water in ml = 1 L = 1000 ml

    Volume of water in ml = 10000 * 1000

    Volume of water in ml = 10000000 ml

    we take 38 g = 38 ml

    Now we convert it to ppm

    ppm = (mass of solute / mass of solvent) * 1000000 (1 million)

    ppm of Cl₂ = (38 : 10000000) * 1000000

    ppm of Cl₂ = 0.0000038 * 1000000

    ppm of Cl₂ = 3.8 ppm

    C. Given data

    Concentration of F⁻ (Fluoride ion) = 2.4 ppm

    Molarity = ?

    Solution

    As we know that 1 ppm = 0.001 g / L

    2.4 ppm = 2.4 * 0.001 g/L

    2.4 ppm = 0.0024 g/L

    Mass of flouride ions = 0.0024 g

    Now we find number of moles

    moles = mass / molar mass

    molar mass of F⁻ = 19 g/mol

    moles of F⁻ = 0.0024 g / 19 g/mol

    moles of F⁻ = 0.0002 mol

    Molarity = mol of solute / liter of solution

    Molarity = 0.0002 mol / 1 L

    Molarity = 0.0002 mol / L

    D. Given data

    Concentration of NO₃⁻ (nitrate ion) = 45 ppm

    Molarity = ?

    Solution

    As we know that 1 ppm = 0.001 g / L

    45 ppm = 45 * 0.001 g/L

    45 ppm = 0.045 g/L

    Mass of nitrate ions = 0.045 g

    Now we find number of moles

    moles = mass / molar mass

    molar mass of NO₃⁻ = 62 g/mol

    moles of NO₃⁻ = 0.045 g / 62 g/mol

    moles of F⁻ = 0.0007 mol

    Molarity = mol of solute / liter of solution

    Molarity = 0.0007 mol / 1 L

    Molarity = 0.0007 mol / L

    E. Reason of expressing concentration in ppm and ppb

    Scientist prefer ppm and ppb notations when the concentration difference of solute and solvent are very high.

    As water contains contaminants is a very low amount we can say in trace amounts so scientist prefer ppm and ppb rather than molarity.

    Example

    Arcenic is an under ground water contaminant and its concentration of 10 μg/L is dangerous for health.

    Lets change this in to molarity

    mass = 10 μg

    10 μg = 10 / 1000000

    10 μg = 0.00001 g

    now find out moles of Arcenic

    moles = mass / molar mass

    molar mass of arcenic = 75 g/mol

    moles = mass / molar mass

    moles of arcenic = 0.00001 g / 75 g/mol

    moles of arcenic = 0.00000012 mol

    Molarity = moles of solute / litres of solution

    Molarity = 0.00000012 mol / 1 L

    Molarity = 0.00000012 mol / L

    As we can see that in molarity it is a negligible amount so scientists express it in ppm and ppb
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