Ask Question
29 June, 18:20

Calcium fluoride (CaF2) has a solubility constant of 3.45 x 10-11

. What is the molar solubility of CaF2 in water?

4.15 x 10-6 M

5.87 x 10-6 M

2.05 x 10-4 M

3.26 x 10-4 M

+2
Answers (1)
  1. 29 June, 18:43
    0
    Ksp=3.45*10⁻¹¹

    CaF₂ (s) ⇄ Ca²⁺ (aq) + 2F⁻ (aq)

    Ksp=[Ca²⁺][F⁻]²

    [Ca²⁺]=C (CaF₂)

    [F⁻]=2C (CaF₂)

    Ksp=4{C (CaF₂) }³

    C (CaF₂) = ∛ (Ksp/4)

    C (CaF₂) = ∛ (3.45*10⁻¹¹/4) = 2.05*10⁻⁴ mol/L

    2.05*10⁻⁴ M
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Calcium fluoride (CaF2) has a solubility constant of 3.45 x 10-11 . What is the molar solubility of CaF2 in water? 4.15 x 10-6 M 5.87 x ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers