If 3 g of sodium reacts with chlorine, how many grams of sodium chloride will be

produced?

7.63 g of NaCl

Explanation:

The balance chemical equation for given neutralization reaction is,

2 Na + Cl₂ → 2 NaCl

Step 1: Calculate Moles of Na as;

Moles = Mass / A. Mass

Moles = 3.0 g / 22.98 g/mol

Moles = 0.130 mol

Step 2: Find out moles of NaCl produced as;

According to equation,

2 moles of Na produced = 2 moles of NaCl

So,

0.130 moles of Na will produce = X moles of NaCl,

Solving for X,

X = 2 mol * 0.130 mol / 2 mol

X = 0.130 moles of NaCl

Step 3: Calculating Mass of NaCl as;

Mass = Moles * M. Mass

Mass = 0.130 mol * 58.44 g/mol

Mass = 7.63 g of NaCl