Write the nuclear equation for the alpha decay of:

(a) Ra-256

(b) Rn - 219

(c) Po - 211

(d) Pb-210

(e) U-238

The answer to your question is below

Explanation:

Alpha decay occurs when a radioactive atm emits an alpha particle (Helium atom).

a) ²⁵⁶Ra ⇒ ²⁵²₈₄ Po + ⁴₂He

b) ²¹⁹Rn ⇒ ²¹⁵₈₂Pb + ⁴₂He

c) ²¹¹Po ⇒ ²⁰⁷₈₀Hg + ⁴₂Hg

d) ²¹⁰Pb ⇒ ²⁰⁶₇₈Pt + ⁴₂Hg

e) ²³⁸U ⇒ ²³⁴₈₈U + ⁴₂Hg