What is the buffer component ratio, (bro-) / (hbro) of a bromate buffer that has a ph of 8.08. ka of hbro is 2.3 x 10-9?

Question

Sammy Ferrell

Chemistry

21 March, 14:27

What is the buffer component ratio, (bro-) / (hbro) of a bromate buffer that has a ph of 8.08. ka of hbro is 2.3 x 10-9?

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Answers (1)

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Emiliano · Answer 1

pKa = - log (ka)

= - log (2.3*10^-9)

= 8.64

Now pH can be calculated using equation:

pH=pka+log (BrO-) / (HBrO)

8.08 = 8.64+log (BrO-) / (HBrO)

log (BrO-) / (HBrO) = 8.08-8.64

= - 0.56

(BrO-) / (HBrO) = 10^-0.56

=0.275