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21 March, 14:27

What is the buffer component ratio, (bro-) / (hbro) of a bromate buffer that has a ph of 8.08. ka of hbro is 2.3 x 10-9?

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  1. 21 March, 14:39
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    pKa = - log (ka)

    = - log (2.3*10^-9)

    = 8.64

    Now pH can be calculated using equation:

    pH=pka+log (BrO-) / (HBrO)

    8.08 = 8.64+log (BrO-) / (HBrO)

    log (BrO-) / (HBrO) = 8.08-8.64

    = - 0.56

    (BrO-) / (HBrO) = 10^-0.56

    =0.275
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