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13 December, 23:30

A total of 25.6 kj of hear energy is added to a 5.18l sample of helium at. 987atm The gas is allowed to expand against a fixed external pressure to a volume of 18.4l

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  1. 13 December, 23:58
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    A total of 25.6 kj of hear energy is added to a 5.18l sample of helium at. 987atm The gas is allowed to expand against a fixed external pressure to a volume of 18.4l

    A) calculate the work done on or by the helium gas units of joules, J.

    B) what is the change in the helium a internal energy in units kilojoules, KJ?

    A. Workdone by helium, W = - 1.322KJ

    B. Internal energy, DE = 24.278KJ

    Explanation:

    Workdone can be defined as the force moving through a distance. For a gaseous system, when the volume of the gas expands, the system is losing energy. Therefore,

    W = - P*DV

    Where P is the pressure in pascal

    DV is the change in volume in m3

    DV = Vfinal - Vinitial

    = 18.4 - 5.18

    = 13.22L

    W = - (0.987 * 13.22)

    = - 13.0481L. atm

    Converting L. atm to joule,

    = - 13.0481 * 101.325

    = - 1322.099J

    = - 1.322KJ

    If the system loses heat, Q the rection occurring is Exothermic.

    Heat is the transfer of energy from one system to another.

    Q = mcDT

    Where m is the mass of the system

    C is the specific heat capacity

    Q = 25.6KJ

    Internal energy is the summation of the heat supplied to a system and the workdone by the system

    DE = Q + W

    DE = 25.6 + (-1.322)

    = 24.278KJ
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