How many moles of calcium carbonate are in 63.8g of calcium carbonate

Question

Elsie Hood

Chemistry

16 May, 21:32

How many moles of calcium carbonate are in 63.8g of calcium carbonate

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Answers (1)

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Liana Conner · Answer 1

0.590 mol of calcium carbonate are in 63.8 g of calcium carbonate.

Explanation:

Chemical substances are framed with respect of their molar quantity, as these are molar ratios, not mass, that occur in stoichiometrically balanced equations. We divide mass by the molar mass of a single molecule or unit of formula to extract moles from mass.

In order to start calculation, firstly the molar mass of calcium carbonate is needed to be detected as follows:

The molar mass of calcium = 40.08 g/mol, carbon is = 12.01 g/mol while for oxygen = 16.00 g/mol.

Thus adding above quantities to calculate molar mass of calcium carbonate: 40.08 + 12.01 + 3 (16.00) = 108.09 g/mol.

Now by dividing the mass of calcium carbonate to its molar mass:

63.8g / 108.09 g/mol = 0.590 mol of calcium carbonate.