28 January, 11:22
2. What is the final temperature of a gas when the volume at 15.0 degrees Celsius was 15 L and changed to 5.0 L if the pressure remains constant?
28 January, 12:05
Data obtained from the question include:
V1 (initial volume) = 15L
T1 (initial temperature) = 15°C = 15 + 273 = 288K
V2 (final volume) = 5L
T2 (final temperature) = ?
Since the pressure is constant, the gas is obeying Charles' law.
Using the Charles' law equation V1/T1 = V2/T2, the final temperature of the gas can be obtained as follow:
V1/T1 = V2/T2
15/288 = 5/T2
Cross multiply to express in linear form as shown below:
15 x T2 = 288 x 5
Divide both side by 15
T2 = (288 x 5) / 15
T2 = 96K
Now, we need to convert 96K to celsius temperature. This is illustrated below
°C = K - 273
°C = 96 - 273
°C = - 177°C
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» 2. What is the final temperature of a gas when the volume at 15.0 degrees Celsius was 15 L and changed to 5.0 L if the pressure remains constant?