To what Celsius temperature must 67.0 mL of krypton gas at 18.0°C be changed so the volume will triple? Assume the pressure and the amount of gas are held constant. Enter your answer to four significant figures.

Question

Colin Houston

Chemistry

24 July, 03:56

To what Celsius temperature must 67.0 mL of krypton gas at 18.0°C be changed so the volume will triple? Assume the pressure and the amount of gas are held constant. Enter your answer to four significant figures.

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Answers (1)

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Alfredo Mccarthy · Answer 1

Answer: 600°C

Explanation:

This reaction is explained by Charles' law as the pressure is constant.

From the question, we obtained:

V1 = 67mL

T1 = 18°C = 18 + 273 = 291K

V2 = 3V1 (Vol is tripled) = 3x67 = 201mL

T2 = ?

Applying the Charles' law,

V1 / T1 = V2 / T2

67/291 = 201 / T2

Cross multiply to express in linear form.

67xT2 = 291x201

Divide both side by 67, we have:

T2 = (291x201) / 67

T2 = 873K

Converting to Celsius temperature, we have

T°C = K - 273

T°C = 873 - 273 = 600°C