A 5.0L balloon in a freezer is at a temperature of - 50˚C has a pressure of 800 mm Hg. What will be the new pressure (in mm Hg) if the balloon is taken out and placed in a warm room (Temperature 37˚C) and the volume expands to 7.0 L? Your answer

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Javion Ware

Chemistry

21 February, 21:23

A 5.0L balloon in a freezer is at a temperature of - 50˚C has a pressure of 800 mm Hg. What will be the new pressure (in mm Hg) if the balloon is taken out and placed in a warm room (Temperature 37˚C) and the volume expands to 7.0 L? Your answer

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Vaughan · Answer 1

To calculate the new pressure, we need to relate pressure with the temperature and the volume of the system. For simplification, we assume that it is an ideal gas so we use the equation PV = nRT where nR is a constant term. We calculate as follows:

P1V1/T1 = P2V2/T2

800 (5.0) / 223.15 = P2 (7.0) / 310.15

P2 = 794.21 mmHg