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12 October, 12:35

Solid calcium carbonate (CaCO3) reacts with hydrochloric acid (HCI) to form carbon dioxide, water, and

calcium chloride (CaCl), according to this equation:

CaCO3 (s) + 2HCl (aq) - CaCl2 (aq) + H2O (aq) + CO2 (g)

Which of these actions would increase the rate of this reaction? Check all that apply.

using a more concentrated HCl solution

crushing the CaCO3 into a fine powder

increasing the pressure on the system

+3
Answers (2)
  1. 12 October, 12:45
    0
    Using a more concentrated HCl solution and Crushing the CaCO₃ into a fine powder makes the reaction to occur at a faster rate.

    Explanation:

    CaCO₃ (s) + 2HCl (aq) → CaCl₂ (aq) + H₂O (aq) + CO₂ (g)

    When calcium carbonate reacts with hydrochloric acid, it gives out carbon-dioxide in the form of bubbles and there is a formation of calcium chloride in aqueous medium.

    The rate of the reaction can be increased by

    Using a more concentrated HCl solution Crushing the CaCO₃ into a fine powder

    When concentrated acid is used instead of dilute acid then the reaction will occur at a faster rate.

    When CaCO₃ is crushed into a fine powder then the surface area will increases thereby increasing the rate of the reaction.
  2. 12 October, 14:08
    0
    Answer: 1 & 2
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