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14 June, 11:03

If 18 mL of methanol is used to make an aqueous solution that is 15% methanol by volume, how many mL of solution is produced?

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  1. 14 June, 11:18
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    120.0 mL.

    Explanation:

    As it is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.

    We suppose that the initial W% of methanol is 100.0 %

    ∴ (W%V) before dilution = (W%V) after dilution.

    W% before dilution = 100.0 %, V before dilution = 18.0 mL.

    W% after dilution = 15.0 %, V after dilution = ? mL.

    ∴ V after dilution = (W%V) before dilution/W% after dilution = (100.0 %) (18.0 mL) / (15.0%) = 120.0 mL.
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