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10 January, 19:21

Using the equation below, calculate the number of grams of CO that can react completely with 78.9 g Fe2O3

Fe2O3 (s) + 3CO (g) → 2Fe (s) + 3CO2 (g)

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  1. 10 January, 19:38
    0
    41.51 g of CO

    Explanation:

    The balance chemical equation for given double displacement reaction is,

    Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

    Step 1: Calculate moles of Fe₂O₃:

    Moles = Mass / M. Mass

    Moles = 78.9 g / 159.68 g/mol

    Moles = 0.494 moles

    Step 2: Calculate moles of CO:

    According to equation,

    1 mole of Fe₂O₃ reacted with = 3 moles of CO

    so,

    0.494 moles of Fe₂O₃ will react with = X moles of CO

    Solving for X,

    X = 0.494 mol * 3 mol : 1 mol

    X = 1.482 moles of CO

    Step 3: Calculate Mass of CO as:

    Mass = Moles * M. Mass

    Mass = 1.482 mol * 28.01 g/mol

    Mass = 41.51 g of CO
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